Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 91

Answer

$$-14q^{2}+11q-14$$

Work Step by Step

Initial equation: $-3(4q^{2}-3q+2)+2(-q^{2}+q-4)$ First, distribute the $-3$ to the first set of parenthesis, and the $2$ to the second: $$-12q^{2}+9q-6-2q^{2}+2q-8$$ Then combine like terms to arrive at the final answer: $$-14q^{2}+11q-14$$
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