## Precalculus (6th Edition)

$\emptyset \cap Q = \emptyset$
RECALL: (1) $\emptyset$ is the empty set (2) The symbol $\cap$ represents intersection of sets which lists down in a set the elements that are common to the given sets. Since the empty set has no elements., then its intersection with any other set will also be empty. Thus, $\emptyset \cap Q = \emptyset$