## Precalculus (6th Edition)

Published by Pearson

# Chapter R - Review of Basic Concepts - R.1 Sets - R.1 Exercises - Page 8: 60

false

#### Work Step by Step

$A \subset B$ if all elements of set A are also elements of set B. Note that $0$ is an element of the set on the left but is not an element of D. This means that \$\left\{0, 2\right\}S is NOT a subset of D. Therefore, the given statement is false.

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