## Precalculus (6th Edition)

Published by Pearson

# Chapter R - Review of Basic Concepts - R.1 Sets - R.1 Exercises - Page 8: 108

#### Answer

$\left\{0, 2, 4\right\}$

#### Work Step by Step

$x \in Q$ and $x \in R$ means that the elements of the given set are in Q and are also in R. This is actually the definition of the intersection of the sets Q and R. Thus, the given set is equivalent to: $Q \cap R = \left\{0, 2, 4\right\}$

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