Answer
$ \frac{1}{a^{23}}$
Work Step by Step
$\frac{a^{-6}(a^{-8})}{a^{-2}(a^{11})}=\frac{a^{-6-8}}{a^{-2+11}}=\frac{a^{-14}}{a^9}=\frac{1}{a^{9+14}}=\frac{1}{a^{23}}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 94
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