Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 93

Answer

$-8y^{11}p$

Work Step by Step

$\frac{-8y^7p^{-2}}{y^{-4}p^{-3}}=-8y^{7+4}p^{-2+3}=-8y^{11}p$
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