Answer
$\color{blue}{66}$
Work Step by Step
RECALL:
$(a+b)(a^2-ab+b^2) = a^3+b^3$
Note that:
$\sqrt[3]{2^2} = (\sqrt[3]{2})^2$
$16=4^2$
Thus, if we let
$a=\sqrt[3]{2}$ and $b=4$
The expression above becomes:
$=(a+b)(a^2-ba+b^2)$ which is equivalent to $(a+b)(a^2-ab+b^2)$
Therefore, using the formula in the recall part above, the given expression simplifies to:
$=(\sqrt[3]{2})^3+4^3
\\=2+64
\\=\color{blue}{66}$
