Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 68

Answer

$(3m+1)(2m-5)$

Work Step by Step

Step 1. Find factors of $6$ as $(2)(3)$, and find factors of $-5$ as $(-5)(1)$ Step 2. Find the sum of cross product of the factors as $(3)(-5)+(2)(1)=-13$ Step 3. We have $6m^2-13m-5=(3m+1)(2m-5)$
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