Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 83: 59

Answer

$6m^2-3m+5$

Work Step by Step

Step 1. Rewrite and factor the numerator as $30m^3-9m^2+22m+5=30m^3+6m^2-15m^2-3m+25m+5=6m^2(5m+1)-3m(5m+1)+5(5m+1)=(5m+1)(6m^2-3m+5)$ Step 2. We have $\frac{30m^3-9m^2+22m+5}{5m+1}=\frac{(5m+1)(6m^2-3m+5)}{5m+1}=6m^2-3m+5$
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