## Precalculus (6th Edition)

$\color{blue}{3(z-4)^2(3z-11)}$
Factor out the GCF $3(z-4)^2$ to obtain: $=3(z-4)^2[1+3(z-4)]$ Distribute $3$ then combine like terms to obtain: $\\=3(z-4)^2(1+3z-12) \\=\color{blue}{3(z-4)^2(3z-11)}$