Answer
$\{(1,2),(1,-2),(-1,2),(-1,-2)\}$
Work Step by Step
1. Multiply 4 to the first equation to get $8x^2+4y^2=24$
2. Add the result to the second equation and get $9x^2=9$, thus $x=\pm1$
3. For $x=1$, we have $y^2=6-2x^2=4$, thus $y=\pm2$
4. For $x=-1$, we have $y^2=6-2x^2=4$, thus $y=\pm2$
5. Thus the solution set is $\{(1,2),(1,-2),(-1,2),(-1,-2)\}$
