Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - Test - Page 958: 23

Answer

$\begin{bmatrix} 8 & 3 \\ 0 & -11 \\ 15&19 \end{bmatrix}$

Work Step by Step

$3\begin{bmatrix} 2 & 3 \\ 1 & -4 \\ 5&9 \end{bmatrix}-\begin{bmatrix} -2 & 6 \\ 3 & -1 \\ 0&8 \end{bmatrix}=$ $\begin{bmatrix} 6 & 9 \\ 3 & -12 \\ 15&27 \end{bmatrix}-\begin{bmatrix} -2 & 6 \\ 3 & -1 \\ 0&8 \end{bmatrix}=$ $\begin{bmatrix} 8 & 3 \\ 0 & -11 \\ 15&19 \end{bmatrix}$
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