Answer
$\{(3,4),(4,3)\}$
Work Step by Step
1. From the second equation, we have $y=7-x$
2. Use substitution in the first equation, we have $x^2+49-14x+x^2=25$, $2x^2-14x+24=0$ or $x^2-7x+12=0$
3. Factor the equation, we have $(x-3)(x-4)=0$, thus $x=3,4$
4. We have $y=4,3$
5. Thus the solution set is $\{(3,4),(4,3)\}$
