Answer
$\{(3,2,1)\}$
Work Step by Step
Need to add equations (2) and (3) to obtain:
$6y+2z=14~~~(1) $
On multiplying Equation -(3) by (2) , and then add to equation (2) to obtain: $-y+11z=9 ~~~~(2)$
Multiply equation (5) by 6 then add to eq-4 to obtain: $z=1$
Plug $z=1$ in equation-5 to obtain:
$-y+11(1)=9 \implies y=2$
Back substitution for $y=2$ and $z=1$ in equation-1 to solve for $x$: $2x-(5)(2)+(3)(1)=1 \implies x=3$
Solution set: $\{(3,2,1)\}$
