Answer
$\{(\dfrac{2}{3},\dfrac{-3}{2})\}$
Work Step by Step
The system of equations are written as:
$6x+10y=-11~~~(1) \\ 9x+6y=-3 ~~~(2)$
Equation -(1) yields: $x=\dfrac{-11-10y}{6} ~~~~(3)$
Plug $x=\dfrac{-11-10y}{6}$ into the second equation and then solve for $y$ to obtain:
$9(\dfrac{-11-10y}{6})+6y=-3 \\ -9y=\dfrac{27}{2}\\ y=\dfrac{-3}{2}$
Back substitution for $y=\dfrac{-3}{2}$ in equation-3 to obtain:
$x=\dfrac{-11-10(-3/2)}{6} =\dfrac{2}{3}$
Solution set: $\{(\dfrac{2}{3},\dfrac{-3}{2})\}$
