Answer
$\{(0,1)\}$
Work Step by Step
The system of equations are written as:
$2x+6y=6 ~~~(1) \\ 5x+9y=9 ~~~(2)$
Equation -(1) yields: $x=3-3y ~~~~(3)$
Plug $x=3-3y$ into the second equation and then solve for $y$ to obtain:
$5(3-3y)+9y=9 \\ 15-15y+9y= 9 \\ y=1$
Back substitution for $y=1$ in equation-3 to obtain:
$x=3-3=0$
Solution set: $\{(0,1)\}$
