Answer
triangle does not exist.
Work Step by Step
Assume the angle of the bottom left corner be $x$, use the Law of Sines, we have $\frac{sin(x)}{78.3}=\frac{sin(38^\circ50')}{21.9}$, thus $sin(x)=\frac{78.3sin38.83^\circ}{21.9}\approx2.24\gt1$. This means that there is no solution for the angle $x$, thus such triangle does not exist.
