Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Summary Exercises on Applications of Trigonometry and Vectors - Exercises - Page 792: 7

Answer

(a). $10\ mph$ (b) $30\ mph$, along $\vec v$ (c) $11.3\ mph$ SE (southeast) wind.

Work Step by Step

(a). Given $\vec v=6i+8j$, draw a diagram as shown, the speed of the wind is given by $|\vec v|=\sqrt {6^2+8^2}=10\ mph$ (b) We have $3\vec v=18i+24j$, since $|3\vec v|=30\ mph$, it means a $30\ mph$ wind along the direction of $\vec v$ (c) Given $\vec u=-8i+8j$, we have $|\vec u|=\sqrt {(-8)^2+8^2}=8\sqrt 2\approx11.3\ mph$ and the wind direction is SE (southeast)
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