Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Summary Exercises on Applications of Trigonometry and Vectors - Exercises - Page 792: 4

Answer

$15.8\ ft/s$, $71.6^\circ$

Work Step by Step

1. Draw a diagram as shown. 2. The resulting speed of the balloon (blue arrow) will be $v=\sqrt {15^2+5^2}=5\sqrt {10}\approx15.8\ ft/s$ 3. The angle with the horizontal is $\theta$ and $tan\theta=\frac{15}{5}=3$, thus $\theta=atan(3)\approx71.6^\circ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.