Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Quiz - Page 772: 4

Answer

$\frac{63}{4}\ unit^2$

Work Step by Step

Use the given figure, assume side $9$ as the base, the height can be found as $h=7sin(180-150)^\circ=\frac{7}{2}$. Thus the area of the triangle is $A=\frac{1}{2}(9)(\frac{7}{2})=\frac{63}{4}\ unit^2$
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