Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Quiz - Page 772: 3

Answer

$48.0^\circ$

Work Step by Step

Use the Law of Cosines, we have $c^2=a^2+b^2-2ab\ cos(C)$ and $(21.2)^2=(28.4)^2+(16.9)^2-2(28.4)(16.9)cos(C)\approx40232.6$ which gives $cos(C)\approx0.6696$. Thus angle $C=acos(0.6696)\approx48.0^\circ$
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