Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - Quiz - Page 772: 1

Answer

$131.3^\circ$

Work Step by Step

1. Draw a diagram as shown. 2. Use the Law of Sines, we have $\frac{sinB}{b}=\frac{sinC}{c}$ which gives $sinC=\frac{c\ sinB}{b}=\frac{4.54sin30.6^\circ}{7.42}\approx0.31146$. Thus angle $C=asin(0.31146)\approx18.1^\circ$ 3. We can find angle $A=180^\circ-30.6^\circ-18.1^\circ\approx131.3^\circ$
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