Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.1 The Law of Sines - 8.1 Exercises - Page 755: 50

Answer

$$B = 69.1^\circ ,\,\,\,C = 59.7^\circ ,\,\,\,b = 8640{\text{ cm}}$$

Work Step by Step

$$\eqalign{ & A = {\text{51}}.{\text{2}}0^\circ ,\,\,\,c = {\text{7986 cm}},\,\,\,a = {\text{72}}0{\text{8 cm}} \cr & {\text{Use the law of sines to find the angle of }}C \cr & \frac{{\sin C}}{c} = \frac{{\sin A}}{a} \cr & \sin C = \frac{{c\sin A}}{a} \cr & {\text{Substituting }} \cr & \sin C = \frac{{{\text{7986}}\sin \left( {{\text{51}}.{\text{2}}0^\circ } \right)}}{{{\text{72}}0{\text{8}}}} \cr & {\text{Use a calculator}} \cr & \sin C \approx 0.86345629 \cr & C \approx {\sin ^{ - 1}}\left( {0.86345629} \right) \cr & C \approx 59.7^\circ \cr & \cr & {\text{Calculate the angle of }}B \cr & B = 180^\circ - A - C \cr & B = 180^\circ - {\text{51}}.{\text{2}}0^\circ - 59.7^\circ \cr & B = 69.1^\circ \cr & \cr & {\text{Use the law of sines to find side }}b \cr & \frac{b}{{\sin B}} = \frac{a}{{\sin A}} \cr & b = \frac{{{\text{72}}0{\text{8}}\sin \left( {69.1^\circ } \right)}}{{\sin \left( {{\text{51}}.{\text{2}}0^\circ } \right)}} \cr & b \approx 8640{\text{ cm}} \cr & \cr & {\text{Answer}} \cr & B = 69.1^\circ ,\,\,\,C = 59.7^\circ ,\,\,\,b = 8640{\text{ cm}} \cr} $$
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