Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.1 The Law of Sines - 8.1 Exercises - Page 755: 41

Answer

$$B = 20.6^\circ ,\,\,\,C = 116.9^\circ ,\,\,\,c = 20.6{\text{ft}}$$

Work Step by Step

$$\eqalign{ & A = {\text{42}}.{\text{5}}^\circ ,a = {\text{15}}.{\text{6 ft}},b = {\text{8}}.{\text{14 ft}} \cr & {\text{Use the law of sines to find the angle of }}B \cr & \frac{{\sin B}}{b} = \frac{{\sin A}}{a} \cr & \sin B = \frac{{b\sin A}}{a} \cr & {\text{Substituting }} \cr & \sin B = \frac{{\left( {{\text{8}}.{\text{14}}} \right)\sin \left( {{\text{42}}.{\text{5}}^\circ } \right)}}{{{\text{15}}.{\text{6}}}} \cr & {\text{Use a calculator}} \cr & \sin B \approx 0.3525195058 \cr & B \approx {\sin ^{ - 1}}\left( {0.3525195058} \right) \cr & B \approx 20.6^\circ \cr & \cr & {\text{Calculate the angle of }}C \cr & C = 180^\circ - A - B \cr & C = 180^\circ - {\text{42}}.{\text{5}}^\circ - 20.6^\circ \cr & C = 116.9^\circ \cr & \cr & {\text{Use the law of sines to find side }}c \cr & \frac{c}{{\sin C}} = \frac{a}{{\sin A}} \cr & c = \frac{{{\text{15}}.{\text{6}}\sin \left( {116.9^\circ } \right)}}{{\sin \left( {{\text{42}}.{\text{5}}^\circ } \right)}} \cr & c \approx 20.6{\text{ft}} \cr & \cr & {\text{Answer}} \cr & B = 20.6^\circ ,\,\,\,C = 116.9^\circ ,\,\,\,c = 20.6{\text{ft}} \cr} $$
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