Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.1 The Law of Sines - 8.1 Exercises - Page 755: 47

Answer

$$B = 37.77^\circ ,\,\,\,C = 45.43^\circ ,\,\,\,c = 4.174{\text{ft}}$$

Work Step by Step

$$\eqalign{ & A = {\text{96}}.{\text{8}}0^\circ ,\,\,\,\,\,b = {\text{3}}.{\text{589 ft}},\,\,\,\,a = {\text{5}}.{\text{818 ft}} \cr & {\text{Use the law of sines to find the angle of }}B \cr & \frac{{\sin B}}{b} = \frac{{\sin A}}{a} \cr & \sin B = \frac{{b\sin A}}{a} \cr & {\text{Substituting }} \cr & \sin B = \frac{{\left( {{\text{3}}.{\text{589}}} \right)\sin \left( {{\text{96}}.{\text{8}}0^\circ } \right)}}{{{\text{5}}.{\text{818}}}} \cr & {\text{Use a calculator}} \cr & \sin B \approx 0.6125392246 \cr & B \approx {\sin ^{ - 1}}\left( {0.6125392246} \right) \cr & B \approx 37.77^\circ \cr & \cr & {\text{Calculate the angle of }}C \cr & C = 180^\circ - A - B \cr & C = 180^\circ - {\text{96}}.{\text{8}}0^\circ - 37.77^\circ \cr & C = 45.43^\circ \cr & \cr & {\text{Use the law of sines to find side }}c \cr & \frac{c}{{\sin C}} = \frac{a}{{\sin A}} \cr & c = \frac{{a\sin C}}{{\sin A}} \cr & c = \frac{{{\text{5}}.{\text{818}}\sin \left( {45.43^\circ } \right)}}{{\sin \left( {{\text{96}}.{\text{8}}0^\circ } \right)}} \cr & c \approx 4.174{\text{ft}} \cr & \cr & {\text{Answer}} \cr & B = 37.77^\circ ,\,\,\,C = 45.43^\circ ,\,\,\,c = 4.174{\text{ft}} \cr} $$
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