Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.1 The Law of Sines - 8.1 Exercises - Page 754: 29

Answer

$$C = {97^ \circ }34',\,\,\,\,\,\,b = 283.18{\text{m}},\,\,\,\,\,\,\,c = 415.24{\text{m}}$$

Work Step by Step

$$\eqalign{ & A = {39^ \circ }54',\,\,\,a = 268.7{\text{m,}}\,\,\,B = {42^ \circ }32' \cr & \cr & {\text{Find }}C \cr & C = {180^ \circ } - A - B \cr & C = {180^ \circ } - {39^ \circ }54' - {42^ \circ }32' \cr & C = {97^ \circ }34' \cr & \cr & {\text{Use the law of sines to find side }}b \cr & \frac{a}{{\sin A}} = \frac{b}{{\sin B}} \cr & b = \frac{{a\sin B}}{{\sin A}} \cr & b = \frac{{268.7\sin \left( {{{42}^ \circ }32'} \right)}}{{\sin \left( {{{39}^ \circ }54'} \right)}} \cr & {\text{Use a calculator}} \cr & b = 283.18{\text{m}} \cr & \cr & {\text{Use the law of sines to find side }}c \cr & \frac{c}{{\sin C}} = \frac{a}{{\sin A}} \cr & c = \frac{{a\sin C}}{{\sin A}} \cr & c = \frac{{268.7\sin \left( {{{97}^ \circ }34'} \right)}}{{\sin \left( {{{39}^ \circ }54'} \right)}} \cr & {\text{Use a calculator}} \cr & c = 415.24{\text{m}} \cr & \cr & {\text{Answer}} \cr & C = {97^ \circ }34',\,\,\,\,\,\,b = 283.18{\text{m}},\,\,\,\,\,\,\,c = 415.24{\text{m}} \cr} $$
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