#### Answer

$\angle C=95$
$| BC| =\dfrac {18\sin 37}{\sin 95}\approx 10.874;$
$\left| AC\right| =\dfrac {18\sin 48}{\sin 95}\approx 13.4$

#### Work Step by Step

Sum of internal angles of a triangle is $180^0$ then
$\angle C=180-\left( 37+48\right) =95$
From the law of sines
$\dfrac {18}{\sin \angle C}=\dfrac {\left| BC\right| }{\sin 37}=\dfrac {\left| AC\right| }{\sin 48}\Rightarrow \left| BC\right| =\dfrac {18\sin 37}{\sin 95}\approx 10.874;\left| AC\right| =\dfrac {18\sin 48}{\sin 95}\approx 13.4$