Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.1 The Law of Sines - 8.1 Exercises - Page 754: 21

Answer

$$B = {18.50^ \circ },\,\,\,a = 239{\text{yd, }}\,c = 230{\text{yd}}$$

Work Step by Step

$$\eqalign{ & A = {87.2^ \circ },\,\,\,b = 75.9{\text{yd}},\,\,\,C = {74.3^ \circ } \cr & {\text{Find }}B \cr & B = {180^ \circ } - A - C \cr & B = {180^ \circ } - {87.2^ \circ } - {74.3^ \circ } \cr & B = {18.50^ \circ } \cr & \cr & {\text{Use the law of sines to find side }}a \cr & \frac{a}{{\sin A}} = \frac{b}{{\sin B}} \cr & a = \frac{{b\sin A}}{{\sin B}} \cr & a = \frac{{75.9\sin \left( {{{87.2}^ \circ }} \right)}}{{\sin \left( {{{18.50}^ \circ }} \right)}} \cr & {\text{Use a calculator}} \cr & a = 239{\text{yd}} \cr & \cr & {\text{Use the law of sines to find side }}c \cr & \frac{a}{{\sin A}} = \frac{c}{{\sin C}} \cr & c = \frac{{a\sin C}}{{\sin A}} \cr & c = \frac{{239\sin \left( {{{74.3}^ \circ }} \right)}}{{\sin \left( {{{87.2}^ \circ }} \right)}} \cr & c = 230{\text{yd}} \cr & \cr & {\text{Answer}} \cr & B = {18.50^ \circ },\,\,\,a = 239{\text{yd, }}\,c = 230{\text{yd}} \cr} $$
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