#### Answer

$-\tan x$

#### Work Step by Step

$\tan \left( 2\pi -x\right) =\dfrac {\tan 2\pi -\tan x}{1-\tan 2\pi \tan x}=\dfrac {0-\tan x}{1-0\times \tan x}=-\tan x$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$-\tan x$

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