#### Answer

$\dfrac {1+\tan x}{1-\tan x}$

#### Work Step by Step

$\tan \left( \dfrac {\pi }{4}+x\right) =\dfrac {\tan \dfrac {\pi }{4}+\tan x}{1-\tan \dfrac {\pi }{4}\tan x}=\dfrac {1+\tan x}{1-\tan x}$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$\dfrac {1+\tan x}{1-\tan x}$

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