Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 680: 72


$\dfrac {1+\tan x}{1-\tan x}$

Work Step by Step

$\tan \left( \dfrac {\pi }{4}+x\right) =\dfrac {\tan \dfrac {\pi }{4}+\tan x}{1-\tan \dfrac {\pi }{4}\tan x}=\dfrac {1+\tan x}{1-\tan x}$
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