Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 680: 71


$\dfrac {\sqrt {3}\tan \theta +1}{\sqrt {3}-\tan \theta }$

Work Step by Step

$\tan \left( \theta +30\right) =\dfrac {\tan \theta +\tan 30}{1-\tan \theta \tan 30}=\dfrac {\tan \theta +\dfrac {1}{\sqrt {3}}}{1-\dfrac {1}{\sqrt {3}}\tan \theta }=\dfrac {\sqrt {3}\tan \theta +1}{\sqrt {3}-\tan \theta }$
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