Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.1 Radian Measures - 6.1 Exercises - Page 576: 108


$\color{blue}{r \approx 17 \text{ m}}$

Work Step by Step

RECALL: The area of a sector $(A)$ intercepted by a central angle $\theta$ on a circle whose radius is $r$ is given by the formula: $A = \frac{1}{2}r^2\theta$, where $\theta$ is in radian measure. Substitute the given values of the the central angle and the area of the sector to obtain: $A=\frac{1}{2}r^2\theta \\64=\frac{1}{2}(r)(\frac{\pi}{6}) \\64=r(\frac{\pi}{12}) \\\frac{\pi}{12} \cdot 64=r \\16.75516082 =r \\\color{blue}{r \approx 17 \text{ m}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.