## Precalculus (6th Edition)

$\color{blue}{\theta\approx 3.6 \text{ radians}}$
RECALL: The area of a sector $(A)$ intercepted by a central angle $\theta$ on a circle whose radius is $r$ is given by the formula: $A = \frac{1}{2}r^2\theta$, where $\theta$ is in radian measure. Substitute the given values of the area and area of the sector to obtain: $A=\frac{1}{2}r^2\theta \\16=\frac{1}{2}(3.0^2)(\theta) \\16=0.5(9)\theta \\16=4.5\theta \\\frac{16}{4.5}=\theta \\3.\overline{5}=\theta \\\color{blue}{\theta\approx 3.6 \text{ radians}}$