Answer
$\sin A=\frac{n}{p}$
$\cos A=\frac{m}{p}$
$\tan A=\frac{n}{m}$
Work Step by Step
$\sin A=\frac{\text{side opposite}}{\text{hypotenuse}}=\frac{n}{p}$
$\cos A=\frac{\text{side adjacent}}{\text{hypotenuse}}=\frac{m}{p}$
$\tan A=\frac{\text{side opposite}}{\text{side adjacent}}=\frac{n}{m}$
