Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.3 Trigonometric Functions Values and Angle Measures - 5.3 Exercises - Page 531: 12

Answer

$\sin A=\frac{45}{53}$ $\cos A=\frac{28}{53}$ $\tan A=\frac{45}{28}$

Work Step by Step

$\sin A=\frac{\text{side opposite}}{\text{hypotenuse}}=\frac{45}{53}$ $\cos A=\frac{\text{side adjacent}}{\text{hypotenuse}}=\frac{28}{53}$ $\tan A=\frac{\text{side opposite}}{\text{side adjacent}}=\frac{45}{28}$
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