Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Summary Exercises on Functions: Domains and Defining Equations - Exercises - Page 487: 39

Answer

$(-2,6)$.

Work Step by Step

The domain requirement for $f(x)=ln(\frac{-3}{(x+2)(x-6)})$ is $\frac{-3}{(x+2)(x-6)}\gt0$ or $(x+2)(x-6)\lt0$ which gives $-2\lt x\lt 6$ (one factor is negative), in interval notation $(-2,6)$.
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