Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Summary Exercises on Functions: Domains and Defining Equations - Exercises - Page 487: 22

Answer

$[-2,3]\cup[4,\infty)$.

Work Step by Step

The domain requirement for $f(x)=\sqrt {(x-3)(x+2)(x-4)}$ is $(x-3)(x+2)(x-4)\geq0$ which gives $x\geq4$ (all factors are positive or one is zero), $-2\leq x\leq 3$ (only one factor is positive or zero), and in interval notation $[-2,3]\cup[4,\infty)$.
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