Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - Summary Exercises on Functions: Domains and Defining Equations - Exercises - Page 487: 26

Answer

$(-\infty,-\sqrt 7)\cup(-\sqrt 7,\sqrt 7)\cup(\sqrt 7,\infty)$.

Work Step by Step

The domain requirement for $f(x)=\frac{1}{|x^2-7|}$ is $|x^2-7|\ne0$ or $x\ne\pm\sqrt 7$ , in interval notation $(-\infty,-\sqrt 7)\cup(-\sqrt 7,\sqrt 7)\cup(\sqrt 7,\infty)$.
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