Answer
See table.
Work Step by Step
Step 1. Given $f(x)=-8x^4+3x^3-6x^2+5x-7$, we can identify 4 sign changes indicating that there could be 4, 2, or 0 positive zeros. Put the numbers in the table.
Step 2. $f(-x)=-8x^4-3x^3-6x^2-5x-7$, we can identify 0 sign changes indicating that there will be no negative zero. Put the numbers in the table.
Step 3. There should be 4 total zeros. thus the number of nonreal zeros will be the remaining after taking real zeros into account. Complete the table as shown.