Answer
$x=-1$ with a multiplicity of $2$
$x=1$ with a multiplicity of $3$
$x=\pm\sqrt {10}$ each with a multiplicity of $1$
Work Step by Step
Step 1. Give $f(x)=(x+1)^2(x-1)^3(x^2-10)$, we can find the first zero as $x=-1$ with a multiplicity of $2$
Step 2. We can find the second zero as $x=1$ with a multiplicity of $3$
Step 3. Let $(x^2-10)=0$, we have $x=\pm\sqrt {10}$ each with a multiplicity of $1$