#### Answer

Option B

#### Work Step by Step

RECALL:
The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units.
The given equation can be written as $(x-3)^2+(y-2)^2=5^2$
Thus, the given equation has its center at $(3, 2)$ and has a radius of 5 units.
Therefore, its graph is the one in Option B.