Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.2 Circles - 2.2 Exercises - Page 200: 15

Answer

$\color{blue}{x^2+(y-4)^2=16}$
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Work Step by Step

RECALL: The center-radius form of a circle's equation is $(x-h)^2+(y-k)^2=r^2$ with center at $(h, k)$ and a radius of $r$ units. Thus, the given circle's equation in center-radius form is: $(x-0)^2+(y-4)^2=4^2 \\\color{blue}{x^2+(y-4)^2=16}$ To graph the circle, perform the following steps: (1) Plot the center. (2) Plot the points 4 units above, below, to the left, and to the right of the center. (3) Connect the four points in Step 2 using a curve to form a circle.
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