Answer
$(0, 5)$
Work Step by Step
RECALL:
The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units.
The given equation can be written as:
$(x-0)^2+(y-5)^2=3^2$
Thus, the center of the circle is at $(0, 5)$.