#### Answer

$(4, -7)$

#### Work Step by Step

RECALL:
The circle $(x-h)^2+(y-k)^2=r^2$ has its center at $(h, k)$ and a radius of $r$ units.
The given equation can be written as:
$(x-4)^2+(y-(-7))^2=3^2$
Thus, the center of the circle is at $(4, -7)$.