Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1026: 73



Work Step by Step

$\sum ^{1000}_{i=1}i=\dfrac {\left( a_{1}+a_{1000}\right) \times n}{2}\Rightarrow a_{1}=1;a_{1000}=1000;n=1000\Rightarrow S=\dfrac {1+1000}{2}\times 1000=500500$
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