Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1026: 68



Work Step by Step

$\sum ^{5}_{i=1}\left( i-8\right) =\sum ^{5}_{i=1}i-\sum ^{5}_{i=1}8=\dfrac {n\left( n+1\right) }{2}-8n=\dfrac {5\times \left( 5+1\right) }{2}-8\times 5=15-40=-25$
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