Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - 11.2 Arithmetic Sequences and Series - 11.2 Exercises - Page 1026: 69

Answer

140

Work Step by Step

$\sum ^{10}_{j=1}\left( 2j+3\right) =2\sum ^{10}_{j=1}j+\sum ^{10}_{j=1}3=2\times \dfrac {n\times \left( n+1\right) }{2}+3\times n=2\times \dfrac {10\times 11}{2}+3\times 10=140$
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