Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 997: 40

Answer

$${\text{The equation does not represent a graph}}$$

Work Step by Step

$$\eqalign{ & {\left( {x + 7} \right)^2} + {\left( {y - 5} \right)^2} + 4 = 0 \cr & {\text{Subtract 4 from each side of the equation}} \cr & {\left( {x + 7} \right)^2} + {\left( {y - 5} \right)^2} + 4 - 4 = - 4 \cr & {\left( {x + 7} \right)^2} + {\left( {y - 5} \right)^2} = - 4 \cr & {\text{The equation is in the form }}{\left( {x - h} \right)^2} + {\left( {y - k} \right)^2} = {r^2} \cr & {\text{We can note that }}{r^2}{\text{ is negative, }} \cr & {\text{then the equation does not represent a graph}} \cr} $$
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