Answer
$${\text{point}}$$
Work Step by Step
$$\eqalign{
& \frac{{{{\left( {x - 4} \right)}^2}}}{8} + \frac{{{{\left( {y + 1} \right)}^2}}}{2} = 0 \cr
& {\text{The equation is in the form }}\frac{{{{\left( {x - h} \right)}^2}}}{{{a^2}}} + \frac{{{{\left( {y - k} \right)}^2}}}{{{b^2}}} = 0 \cr
& {\text{The righ side is 0}} \cr
& {\text{Therefore, the equation represents a point centered at }}\left( {h,k} \right) \cr
& {\text{Point centered at }}\left( {4, - 1} \right) \cr
& {\text{Graph}} \cr} $$
