Chapter 10 - Analytic Geometry - 10.4 Summary of the Conic Sections - 10.4 Exercises - Page 997: 37

$${\text{parabola}}$$

$$\eqalign{ & {x^2} = 4y - 8 \cr & {\left( {x - 0} \right)^2} = 4\left( {y - 2} \right) \cr & {\text{The equation is in the form }}{\left( {x - h} \right)^2} = 4p\left( {y - k} \right) \cr & {\text{Therefore, the equation represents a parabola}} \cr & {\text{Graph}} \cr} $$